Denote the (positive) speeds of objects just after explosion as and
, and their masses as
and
. The directions of
and
are the opposite.
Then conservation of impulse gives us because the speed just before the explosion was zero. The conservation of energy gives
(the chemical energy that becomes kinetic).
Solving this system of equations is easy:
substitute it to...
Denote the (positive) speeds of objects just after explosion as and
, and their masses as
and
. The directions of
and
are the opposite.
Then conservation of impulse gives us because the speed just before the explosion was zero. The conservation of energy gives
(the chemical energy that becomes kinetic).
Solving this system of equations is easy:
substitute it to the second equation and obtain
so
and
In numbers, they will be equal to
For the second part of the question we have to consider an angle between the velocity of the first object and a horizontal line, and write the equations of horizontal and vertical movements of both bodies.
No comments:
Post a Comment