During the friction with the fur of the cat, the balls acquire electric charge. As the balls are spherical, we can consider that the charge is situated in its Center and we can apply the Coulomb's law for the electrostatic interaction, between two particles charged.
a)
F = (Kq1q2)/d2
where:
K = 9*10^9 Nm^2/C^2, the electric constant for the vacuum.
q1 = q2, the electric charges that the tennis balls acquire during the rubbing with...
During the friction with the fur of the cat, the balls acquire electric charge. As the balls are spherical, we can consider that the charge is situated in its Center and we can apply the Coulomb's law for the electrostatic interaction, between two particles charged.
a)
F = (Kq1q2)/d2
where:
K = 9*10^9 Nm^2/C^2, the electric constant for the vacuum.
q1 = q2, the electric charges that the tennis balls acquire during the rubbing with the cat.
d, is the distance measured between the centers of the tennis balls.
Solving for the distance d and substituting, we have:
d = sqrt(Kq^2)/F
d = sqrt(9*10^9(3.5*10^-9)^2)/(6.0 x 10^-5)
d = 4.28*10^-2 m = 4.28 cm
The distance between the centers of the balls is d = 4.28 cm.
b) The balls acquire electric charges of the same sign, so the force is repulsive.
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