The balanced equation for this reaction is:
+
->
+
Step 1: Determine the molar mass of and
.
Since "grams" are involved in this calculation, we will need to use the following mole conversion factors: 1 mole = molar mass AND 1 mole = molar mass
. So, before we start the main calculation, let's go ahead and determine the molar mass...
The balanced equation for this reaction is:
+
->
+
Step 1: Determine the molar mass of and
.
Since "grams" are involved in this calculation, we will need to use the following mole conversion factors: 1 mole = molar mass AND 1 mole = molar mass
. So, before we start the main calculation, let's go ahead and determine the molar mass of
and
.
The molar mass of a substance is determined by multiplying the atomic mass of each atom in the substance times its subscript and adding the resulting answers.
Molar mass of = (1)(14.007) + 3(1.008) = 17.031 g/mol
Molar mass of = (2)(18.998) = 37.996 g/mol
Therefore,
1 mole = 17.031 grams
1 mole = 37.996 grams
Step 2: Determine the mole ratio between and
.
The mole ratio between two substances is equal to the ratio between the coefficients of the substances. According the reaction above, the coefficient for is 2 and the coefficient for
is 5.
Therefore, the mole ratio between and
is:
2 moles = 5 moles
Step 3: Perform the stoichiometry calculation.
The stoichiometry calculation will take the general form of:
given amount x mole conversion factor x mole ratio x
mole conversion factor
Therefore,
66.6 g x (1 mol/17.031) x (5 mol
/2 mol
) x (37.996 g/1mol) = 371 g
*Notice that the conversion factors and mole ratio are oriented such that all units and substances cancel out except grams of .
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