Another way to calculate the area of this triangle is by noticing that two of the given points have the same x-coordinates, and two of the given points have the same y-coordinates. This means one side of the triangle is parallel to the x-axis, and another side is parallel two the y-axis. These sides are perpendicular to each other, so this is a right triangle. The area of the right triangle is half of the...
Another way to calculate the area of this triangle is by noticing that two of the given points have the same x-coordinates, and two of the given points have the same y-coordinates. This means one side of the triangle is parallel to the x-axis, and another side is parallel two the y-axis. These sides are perpendicular to each other, so this is a right triangle. The area of the right triangle is half of the product of the perpendicular sides (a special case of the more general formula for the area of a triangle: area = 1/2 of base times height.)
The length of the side with the ends at the vertices (-6,6) and (5,6) (the side parallel to the x-axis) is
`l_1 = 5 - (-6) = 11`
The length of the side with the ends at the vertices (5, -1) and (5,6) (the side parallel to the y-axis) is
`l_2 = 6 - (-1) = 7`
So the area of the triangle is
`A = 1/2*l_1*l_2 = 1/2*77 = 38.5` .
The area of the triangle is 38.5.
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